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sum(r=0)^n nCr (sin rx) is equal to...

`sum_(r=0)^n nC_r (sin rx)` is equal to

A

`2^(n).cos^(n)""(x)/(2).sin""(nx)/(2)`

B

`2^(n).sin^(n)""(x)/(2).cos""(nx)/(2)`

C

`2^(n+1).cos^(n)""(x)/(2).sin""(nx)/(2)`

D

`2^(n+1).sin^(n)""(x)/(2).cos""(nx)/(2)`

Text Solution

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The correct Answer is:
A
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DISHA PUBLICATION-BINOMIAL THEOREM -EXERCISE-2 (CONCEPT APPLICATOR)
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