If a1,a2,a3,...,a(n+1) are in A.P. , the...

If `a_1,a_2,a_3,...,a_(n+1)` are in A.P. , then `1/(a_1a_2)+1/(a_2a_3)....+1/(a_na_(n+1))` is

`(n-1)/(a_(1)a_(n+1))`

`(1)/(a_(1)a_(n+1))`

`(n+1)/(a_(1)a_(n+1))`

`(n)/(a_(1)a_(n+1))`

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Let a_1,a_2,a_3 …. a_n be in A.P. If 1/(a_1a_n)+1/(a_2a_(n-1)) +… + 1/(a_n a_1) = k/(a_1 + a_n) (1/a_1 + 1/a_2 + …. 1/a_n) , then k is equal to :

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