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The AM, HM and GM between two number are...

The AM, HM and GM between two number are `(144)/(15)`, 15 and 12, but not necessarily in this order then, HM, GM and AM respectively are

A

`(144)/(15),12, 15`

B

`(144)/(15), 15, 12`

C

`15, 12, (144)/(15)`

D

`12, 15, (144)/(15)`

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The correct Answer is:
To solve the problem, we need to identify the Arithmetic Mean (AM), Geometric Mean (GM), and Harmonic Mean (HM) from the given values: \( \frac{144}{15} \), 15, and 12. We will determine which value corresponds to AM, GM, and HM based on their properties. ### Step-by-Step Solution: 1. **Understanding the Means**: - The Arithmetic Mean (AM) of two numbers \( A \) and \( B \) is given by: \[ AM = \frac{A + B}{2} \] - The Geometric Mean (GM) is given by: \[ GM = \sqrt{AB} \] - The Harmonic Mean (HM) is given by: \[ HM = \frac{2AB}{A + B} \] 2. **Properties of the Means**: - We know that \( AM \geq GM \geq HM \) for any two positive numbers \( A \) and \( B \). This means that AM is the largest, GM is in the middle, and HM is the smallest. 3. **Identifying the Values**: - We have three values: \( \frac{144}{15} \approx 9.6 \), 15, and 12. - Let's compare these values: - \( \frac{144}{15} \approx 9.6 \) - 12 - 15 - From this comparison, we can see that: \[ HM < GM < AM \] Thus, \( \frac{144}{15} \) must be HM, 12 must be GM, and 15 must be AM. 4. **Conclusion**: - Therefore, we can conclude: - HM = \( \frac{144}{15} \) - GM = 12 - AM = 15 ### Final Answer: - HM = \( \frac{144}{15} \) - GM = 12 - AM = 15
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