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In the coefficients of rth, `(r+1)t h ,a n d(r+2)t h` terms in the binomial expansion of `(1+y)^m` are in A.P., then prove that `m^2-m(4r+1)+4r^2-2=0.`

A

`m^(2) - m(4r -1) + 4 r^(2) - 2 =0`

B

`m^(2) - m(4r + 1) + 4r^(2) + 2 =0`

C

`m^(2) - m(4r + 1) + 4r^(2) - 2 = 0`

D

`m^(2) - m(4r -1) + 4r^(2) + 2 = 0`

Text Solution

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The correct Answer is:
C
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