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If a variable line drawn through the intersection of the lines `x/3+y/4=1`and `x/4+y/3=1` meets the coordinate axes at `A` and `B, (A !=B),` then the locus of the midpoint of `AB` is (A) `6xy = 7 (x+y)` (B) `4 (x+y)^2 - 28(x+y) + 49 =0` (C) `7xy = 6(x+y)` (D) `14 (x+y)^2 - 97(x+y) + 168 = 0`

A

`7xy=6(x+y)`

B

`4(x+y)^(2)-28(x+y)+49=0`

C

`6xy=7(x+y)`

D

`14(x+y)^(2)-97(x+y)+168=0`

Text Solution

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The correct Answer is:
A
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DISHA PUBLICATION-STRAIGHT LINES AND PAIR OF STRAIGHT LINES-EXERCISE 2: CONCEPT APPLICATOR
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