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Given three points P,Q,R with P(5,3) and...

Given three points P,Q,R with P(5,3) and R lies on the x-axis. If equation of RQ is `x-2y=2` and PQ is parallel to the x-axis, then the centroid of `DeltaPQR` lies on the line:

A

`2x+y-9=0`

B

`x-2y+1=0`

C

`5x-2y=0`

D

`2x-5y=0`

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • Given three points P, Q, R with P (5, 3) and R lies on the x-axis. If equation of RQ is x-2y=2 and PQ is parallel to x-axis, then centroid of Delta PQR lies on the line

    A
    `2x+y-9=0`
    B
    `x-2y+1=0`
    C
    `5x-2y=0`
    D
    `2x-5y=0`

  • The point P(a,b) lies on the straight line 3x+2y=13 and the point Q(b,a) lies on the straight line 4x-y=-5 , then the equation of the line PQ is

    A
    x-y=5
    B
    `x+y=5`
    C
    `x+y=-5`
    D
    `x-y=-5`

  • If P=(1,1),Q=(3,2) and R is a point on x-axis then the value of PR+RQ will be minimum at

    A
    `(5/3,0)`
    B
    `(1/3,0)`
    C
    `(3,0)`
    D
    `(1,0)`

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