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Which of the following is equivalent to `(p ^^q):` (a) `p -> ~q` (b) `~(~p ^^ ~q)` (c) `~(p-> ~q)` (d) Non of these

A

p`rArr`q~= ~p `rArr` ~q

B

~(p`rArr`~q) ~= ~ p`^^`q

C

~(~p`rArr`~q) ~= ~p`^^`q

D

~(~p`hArr`q)~=[~(p`hArr`q)`^^`~(q`rArr`p)]

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The correct Answer is:
C
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DISHA PUBLICATION-MATHEMATICAL REASONING-Exercise-1 : Concept Builder
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