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If g(x)=x-2 is the inverse of the functi...

If g(x)=x-2 is the inverse of the function f(x)=x+2, then graph of g(x) is the image of graph of f(x) about the line y=kx. Here k =

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1

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2

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3

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4

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The correct Answer is:
To solve the problem, we need to determine the value of \( k \) such that the graph of \( g(x) = x - 2 \) is the image of the graph of \( f(x) = x + 2 \) about the line \( y = kx \). ### Step-by-Step Solution: 1. **Identify the Functions**: We have two functions: - \( f(x) = x + 2 \) - \( g(x) = x - 2 \) 2. **Graph the Functions**: - For \( f(x) \): - When \( x = 0 \), \( f(0) = 0 + 2 = 2 \) (point: \( (0, 2) \)) - When \( y = 0 \), \( 0 = x + 2 \) gives \( x = -2 \) (point: \( (-2, 0) \)) - The line passes through points \( (0, 2) \) and \( (-2, 0) \). - For \( g(x) \): - When \( x = 0 \), \( g(0) = 0 - 2 = -2 \) (point: \( (0, -2) \)) - When \( y = 0 \), \( 0 = x - 2 \) gives \( x = 2 \) (point: \( (2, 0) \)) - The line passes through points \( (0, -2) \) and \( (2, 0) \). 3. **Determine the Relationship Between the Two Functions**: - The graph of \( g(x) \) is a downward shift of the graph of \( f(x) \) by 4 units. This can be seen as: \[ g(x) = f(x) - 4 \] 4. **Find the Midpoint**: - The midpoint between the two functions can be calculated as: \[ \text{Midpoint} = \frac{f(x) + g(x)}{2} = \frac{(x + 2) + (x - 2)}{2} = \frac{2x}{2} = x \] - This indicates that the line \( y = x \) is the line of symmetry. 5. **Determine the Value of \( k \)**: - The line of symmetry \( y = x \) can be expressed in the form \( y = kx \), where \( k = 1 \). ### Final Answer: Thus, the value of \( k \) is \( 1 \).
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