A particle travels half the distance with a velocity of `6 ms^(–1)`. The remaining half distance is covered with a velocity of `4 ms^(–1)` for half the time and with a velocity of `8 ms^(–1)` for the rest of the half time. What is the velocity of the particle averaged over the whole time of motion ?

Options

A. `9ms^(-1)`
B. `6ms^(-1)`
C. `5.35 ms^(-1)`
D. `5 ms^(-1)`

Answer

B

Explanation

Average velocity for the second half of the distance is `=(v_(1) + v_(2))/(2) = (4 + 8)/(2) = 6ms^(-1)` Given that first half distance is covered with a velocity of `6ms^(-1)`. Therefore, the average velocity for the whole time of motion is `6ms^(-1)`