A body begins to move with an initial velocity of `2 m s^(-1)` and continues to move at a constant acceleration a.Ten seconds later a second body begins to move from the same point with an initial velocity of `12 m s^(-1)` in the same direction with the same acceleration.What is the maximum acceleration at which it would be possible for the second body to overtake the first ?

Options

A. `1m//s^(2)`
B. `2 m//s^(2)`
C. `1//2 m//s^(2)`
D. `3 m//s^(2)`

Answer

A

Explanation

`a= (v.._(0) -v._(0))/(Delta t)` On substituting `v._(0) = 2m//s, v.._(0) = 12 m//s and Delta t= 10 sec`, we get, `a= 1 m//s^(2)`