A ball is dropped into a well in which the water level is at a depth `h` below the top. If the speed of sound is `C`, then the time after which the splash is heard will be give by.

Options

A. `T= 2h//v`
B. `T= sqrt(((2h)/(g))) + (h)/(v)`
C. `T= sqrt(((2h)/(v)))+ (h)/(g)`
D. `T= sqrt(((h)/(2g))) + (2h)/(v)`

Answer

B

Explanation

Time taken by the stone to reach the water level `t_(1) = sqrt((2h)/(g))`
Time taken by sound to come to the mouth of the well, `t_(2) = (h)/(v)`
`:.` Total time `t_(1)+ t_(2) = sqrt((2h)/(g)) + (h)/(v)`