The moment of inertia of a disc of mass `M` and radius `R` about an axis. Which is tangential to sircumference of disc and parallel to its diameter is.

Options

A. `(3)/(2)MR^(2)`
B. `(2)/(3)MR^(2)`
C. `(5)/(4)MR^(2)`
D. `(4)/(5)MR^(2)`

Answer

C

Explanation

Moment of inertia of disc about its diameter is `I_(d)=(1)/(4)MR^(2)`
MI of disc about a tangent passing through rim and in the plane of disc is
`I=I_(G)+MR^(2)=(1)/(4)MR^(2)+MR^(2)=(5)/(4)MR^(2)`