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The moment of inertia of the body about ...

The moment of inertia of the body about an axis is 1.2 kg `m^(2)`. Initially the body is at rest. In order to produce a rotational kinetic energy of 1500J, an angualr acceleration of 25 `rad/s^(2)` must be applied about the axis for the duration of

A

4 seconds

B

2 seconds

C

8 seconds

D

10 seconds

Text Solution

Verified by Experts

The correct Answer is:
B

`I=1.2kgm^(2),E_(r)=1500J`,
`alpha=25" rad/sec"^(2),omega_(i)=0,t=?`
As `E_(r)=(1)/(2)Iomega^(2)`
`omega=sqrt((2E_(r))/(I))=sqrt((2xx1500)/(1.2))=50" rad/sec"`
From `omega=omega_(1)+alphat,50=0+25t,impliest=2sec`
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