If the density of a small planet is the same as that of earth while the radius of the planet is `0.2` times that of the earth the gravitational on the surface of that planet is :

Options

A. 0.2 g
B. 0.4 g
C. 2g
D. 4g

Answer

A

Explanation

We know that,
`g = (GM)/(R^(2)) = (G((4)/(3) pi R^(3))rho)/(R^(2)) = (4)/(3) pi GR rho `
`(g.)/(g) = (R.)/(R) = (0.2R)/(R) = 0.2 " " therefore g. = 0.2 ` g