The weight of an object in the coal mine, sea level and at the top of the mountain are `W_(1),W_(2)` and `W_(3)` respectively, then

Options

A. `W_(1) lt W_(2) gt W_(3)`
B. `W_(1) = W_(2) = W_(3)`
C. `W_(1) lt W_(2) lt W_(3)`
D. `W_(1) gt W_(2) gt W_(3)`

Answer

A

Explanation

At the surface of earth, the value of g = 9.8 m/`sec^(2)` . If we go towards the centre of earth or we go above the surface of earth, then in both the cases the value of g decreases.
Hence `W_(1) - mg_("mine") , W_(2) = mg_("sea level"), W_(3)- mg_("moun")`
So `W_(1) lt W_(2) gt W_(3) " " ` (g at the sea level = g at the suface of earth )