The acceleration due to gravity on the planet `A` is `9` times the acceleration due to gravity on planet `B`. A man jumps to a height of `2m` on the surface of `A`. What is the height of jump by the same person on the planet `B`?

Options

A. `(2)/(3)` m
B. `(2)/(9)` m
C. 18 m
D. 6m

Answer

C

Explanation

Applying conservation of total mechanical energy principle
`(1)/(2) mv^(2) = mg_(A)h_(A) = mg_(B)h_(B)`
` rArr g_(A) h_(A) = g_(B) h_(B)`
`rArr h_(B) = ((g_(A))/(g_(B))) h_(A) = 9xx 2 = 18` m