How does liquid pressure depend on the d...

How does liquid pressure depend on the depth of a point below the surface of a liquid

`h rho g `

`h rho (g-a)`

`h rho (g +a)`

`2 h rho g ((g +a)/(g -a))`

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The correct Answer is:

When a beaker containing a liquid of density `rho` moves up with an acceleration a, it will work as a lift moving upward with acceleration a. The effective acceleration due to gravity in lift `= (a+ g)`
`therefore` Pressure of liquid of height `h =h rho (a + g )`

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