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The density of ice is xgm//c c and that ...

The density of ice is `xgm//c c` and that of water is `y gm//c c`. What is the change in volume in `c c`, when `m gm` of ice metls?

A

`my (x-y)`

B

`m //(y -x)`

C

`m ((1)/(y) - (1)/(y))`

D

`(y-x) //x`

Text Solution

Verified by Experts

The correct Answer is:
C
Volume of m g of ice = m/x and
volume of m g of water = m/y. So change in volume
` = m/y =m/x =m ((1 )/(y) - (1)/(x))`
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DISHA PUBLICATION-MECHANICAL PROPERTIES OF FLUIDS -EXERCISE-1 CONCEPT BUILDER
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