A pieceo of ice is floating in water . Find the fraction of volume of he piece of ice outside the water
(Given density of ice `=900 kg//m^(3)` and density of water `=1000 kg//m^(3))`

Options

A. `(90)/(103)`
B. `(13)/(103)`
C. `(10)/(103)`
D. `(1)/(103)`

Answer

B

Explanation

Let V be the volume of iceberg and let x be the fraction of volume above water.
Using law of floatation, weight of floating body= weight of liquid displaced by part of the floating body inside the liquid.
Therefore , `v rho _(ice) g = (1-x) V rho _("water") g.`
Using the value of `rho _(ice)and rho _("water")` we get `x = (13//103).`