The cylinderical tube of a spray pump has radius R, One end of which has n fine holes, each of radius r. If the speed of the liquid in the tube is V, the speed of the ejection of the liquid through the holes is :

Options

A. `(VR ^(2))/( nr ^(2))`
B. `( VR ^(2))/( n ^(3) r ^(2))`
C. `(V ^(2) R)/(nr) `
D. `(VR ^(2))/(n ^(2) r ^(2))`

Answer

A

Explanation

Inflow rate of volume of the liquid = Outflow rate of volume of the liquid
`pi R ^(2) V = n pi r ^(2) (v) implies v = (pi R ^(2) V )/( n pi r ^(2)) = (VR ^(2))/( nr ^(2))`