Three rods of Copper, Brass and Steel are welded together to from a Y shaped structure. Area of cross-section of each rod `=4cm^2`. End of copper rod is maintained at `100^@C` where as ends of brass and steel are kept at `0^@C`. Lengths of the copper, brass and steel rods are 46, 13 and 12 cm respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is :

Options

A. 1.2 cal/s
B. 2.4 cal/s
C. 4.8 cal/s
D. 6.0 cal/s

Answer

C

Explanation

Rate of heat flow is given by,
`Q=(KA(theta_(1)-theta_(2)))/(l)`
Where, K = coefficient of thermal conductivity
`l` = length of rod and A = area of cross-section of rod

If the junction temperature is T, then
`Q_("Copper")=Q_("Brass")+Q_("Steel")`
`(0.92xx4(100-T))/(46)`
`=(0.26xx4xx(T-0))/(13)+(0.12xx4xx(T-0))/(12)`
`rArr 200-2T=2T+T rArr T=40^(@)C`
`therefore Q_("Copper")=(0.92xx4xx60)/(46)=4.8cal//s`