On a temperature scale Y, water freezes at `-160^@ ` Y and boils at `-50^@` Y . On this Y scale , a temperature of 340 K is

Options

A. `-73.7^(@)Y`
B. `-233.7^(@)Y`
C. `-86.3^(@)Y`
D. `-106.3^(@)Y`

Answer

C

Explanation

`("Reading on any scale - LEP")/("UFP - LFP") =` constant for all scales
`(340-273)/(373-273)=(""^(@)Y-(-160))/(-50-(-160)) rArr (67)/(100)=(Y+160)/(110)`
`therefore Y=-86.3^(@)Y`