Determine the final result when 200g of water and 20 g of ice at `0^@C` are in a calorimeter having a water equivalent of 30g and 50 g of steam is passed into it at `100^@C`

Options

A. the temperature of the system becomes `169^(@)C`.
B. half of the ice is melted and the temperature of the system remains `0^(@)C`.
C. the temperature remains `100^(@)C` and 53g of steam condenses.
D. the temperature remains `100^(@)C` and the entire steam condenses.

Answer

C

Explanation

If m is the mass of steam condenses, then according to law of calorimetry, heat lost = heat gain
`m xx 540=(250)xx1xx(100-0)+20xx80+20xx1xx(10000)`
`therefore m =53g`
The entire contents will reach the temperature `100^(@)C`.