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Steam at 100^(@)C is passed into 1.1 kg ...

Steam at `100^(@)C` is passed into `1.1 kg` of water contained in a calorimeter of water equivalent `0.02kg` at `15^(@)C` till the temperature of the calorimeter and its content rises to `80^(@)C`. What is the mass of steam condensed? Latent heat of steam = `536 cal//g`.

A

0.13

B

0.065

C

0.26

D

0.135

Text Solution

Verified by Experts

The correct Answer is:
A
`mL+m(100-80)`
`=1.1xx1xx(80-15)+0.02xx(80-15)`
`m xx 540+20m=71.5+1.30`
`560m=72.80" " therefore m=0.130`
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