The two ends of a rod of length `L` and a uniform cross-sectional area `A` are kept at two temperature `T_(1)` and `T_(2)` `(T_(1) gt T_(2))`. The rate of heat transfer. `(dQ)/(dt)`, through the rod in a steady state is given by

Options

A. `(dQ)/(dt)=(k(T_(1)-T_(2)))/(LA)`
B. `(dQ)/(dt)=kLA (T_(1)-T_(2))`
C. `(dQ)/(dt)=(kA(T_(1)-T_(2)))/(L)`
D. `(dQ)/(dt)=(kL(T_(1)-T_(2)))/(A)`

Answer

C

Explanation

`(dQ)/(dt)=(kA(T_(1)-T_(2)))/(L)`
[`(T_(1)-T_(2))` is the temperature difference]