Consider an ideal gas confined in an isolated closed chamber. As the gas undergoes an adiabatic expansion, the average time of collision between molecules increase as `V^q`, where V is the volume of the gas. The value of q is : `(gamma=(C_p)/(C_v))`

Options

A. `(gamma +1)/2`
B. `(gamma -1)/2`
C. `(3gamma + 5)/6`
D. `(3 gamma -5)/6`

Answer

A

Explanation

`tau =1/(sqrt(2pi))d^(2) (N/V) sqrt((3RT)/M), tau propto V/sqrt(T)`
Therefore, `q = (gamma +1)/2`