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When an ideal gas (gamma = 5//3) is heat...

When an ideal gas `(gamma = 5//3)` is heated under constant pressure, what percentage of given heat energy will be utilized in doing external work ?

A

0.4

B

0.3

C

0.6

D

0.2

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaQ = DeltaU + DeltaW`
`rArr (DeltaW)/(DeltaQ) =1 -(DeltaU)/(DeltaQ) = 1- (nC_(y)dT)/(nC_(p)dT)`
`rArr (DeltaW)/(DeltaQ) =1 -(C_(V))/(C_(P)) =1-3/5 = 2/5 = 0.4`
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