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A carnot engine takes 300 cal. of heat ...

A carnot engine takes 300 cal. of heat at 500 k and rejects 150 cal of heat to the sink. The temperature (in k) of sink is __________.

A

1000 K

B

750 K

C

250 K

D

125 K

Text Solution

Verified by Experts

The correct Answer is:
C
`eta=1 -Q_(2)/Q_(1) =1-T_(2)/T_(1) rArr Q_(2)/Q_(1)=T_(2)/T_(1)`
So, `T_(2) =(Q_(2) xx T_(1))/Q_(1) = (150 xx 500)/300 = 250 K`
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DISHA PUBLICATION-THERMODYNAMICS -EXERCISE-1 : CONCEPT BUILDER (Topic-3 CARNOT ENGINE, REFIGERATOR AND SECOND LAW OF THERMODYNAMICS)
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