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One kg of water at 373K is converted int...

One kg of water at `373K` is converted into steam at the same temperature. The volume `1 cm^(3)` of water becomes `1671 cm^(3)` on boiling. Calculate the change in internal energy of the system , if heat of vaporisation is `540 cal g^(-1)`. Given standard atmospheric pressure `=1.013xx10^(5) Nm^(-2)`.

A

`~~` 167 cal

B

`~~` 500 cal

C

540 cal

D

581 cal

Text Solution

Verified by Experts

The correct Answer is:
B
`dW = PDeltaV = 1.01 xx 10^(5) [1671 -1] xx 10^(-6)` Joule
`=(1.01 xx 167)/4.2` cal = 40 cal nearly,
`DeltaQ = DeltaW + DeltaU` or `DeltaU = 540 - 40 = 500` cal
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