The angular frequency of the damped oscillator is given by `omega=sqrt((k)/(m)-(r^(2))/(4m^(2)))` ,where k is the spring constant, m is the mass of the oscillator and r is the damping constant. If the ratio `r^(2)//(m k)` is 8% ,the change in the time period compared to the undamped oscillator

Options

A. increases by 1%
B. increases by 8%
C. decreases by 1%
D. decreases by 8%

Answer

B

Explanation

The change in time period compared to the undamped oscillator increases by 8%.