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Two simple harmonic motions with the sam...

Two simple harmonic motions with the same frequency act on a particle at right angles i.e., along X-axis and Y-axis. If the two amplitudes are equal and the phase difference is `pi//2`, the resultant motion will be

A

a circle

B

an ellipse with the major axis along y-axis

C

an ellipse with the major axis along x-axis

D

a straight line inclined at `45^(@)` to the x-axis

Text Solution

Verified by Experts

The correct Answer is:
A

Equation of two simple harmonic motion
`y=A sin(omega t+phi)" "…(1)`
`x=A sin(omega t+phi+(pi)/(2))impliesx=A cos(omega t+phi)" "…(2)`
On squaring and adding equations (1) and (2),
`x^(2)+y^(2)=A^(2)`
This is an equation of a circle. Hence, resulting motion will be a circular motion.
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DISHA PUBLICATION-OSCILLATIONS -Exercise-1 : Concept Builder (TOPIC 1: Displacement, Phase, Velocity, Acceleration and Energy in S.H.M.)
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  8. The amplitude of a executing SHM is 4cm At the mean position the speed...

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  18. A particle of mass 10 gm is describing S.H.M. along a straight line wi...

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  19. A particle executes SHM with time period 8 s. Initially, it is at its ...

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