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A particle is subjected to two mutually ...

A particle is subjected to two mutually perpendicular simple harmonic motions such that its `X` and `y` coordinates are given by `X=2 sin omegat` , `y=2 sin (omega+(pi)/(4))`
The path of the particle will be:

A

a straight line

B

a circle

C

an ellipse

D

a parabola

Text Solution

Verified by Experts

The correct Answer is:
C
As phace difference `=(pi)/(4)`, the resultant path of particle is an ellipse.
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DISHA PUBLICATION-OSCILLATIONS -Exercise-1 : Concept Builder (TOPIC 1: Displacement, Phase, Velocity, Acceleration and Energy in S.H.M.)
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  4. A point mass oscillates along the x-acis according to the law x = x(0)...

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  6. A body executing linear simple harmonic motion has a velocity of 3 cm...

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  7. The amplitude of a executing SHM is 4cm At the mean position the speed...

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  8. A particle of mass 1 kg is moving in SHM with an amplitude 0.02 m and ...

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  9. If lt E gt and lt U gt denote the average kinetic and the average pote...

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  11. A particle starts with S.H.M. from the mean position as shown in figur...

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  12. The particle executing simple harmonic motion has a kinetic energy K(0...

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  13. A body executes SHM with an amplitude a. At what displacement from the...

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  14. In S.H.M. the ratio of kinetic energy at mean position to the potentia...

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  15. Starting from the origin a body osillates simple harmonicall with a pe...

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  16. A body is executing simple harmonic motion. At a displacement x its po...

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  19. A body is in simple harmonic motion with time period T - 0.5 s and amp...

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  20. A boby is moving in a room with a velocity of 20m//s perpendicular...

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