A body executing linear simple harmonic motion has a velocity of 3 cm/s when its displacement is 4 cm and a velocity of 4 cm/s when its displacement is 3 cm. Then amplitude of oscillation with be

Options

A. 5 cm
B. 7.5 cm
C. 10 cm
D. 12.5 cm

Answer

A

Explanation

Velocity in SHM is given by `v=omega sqrt(a^(2)-y^(2))`
At `y=4" cm"=0.04" m",v=3" m"//"s"`
`:." "3=omega sqrt(a^(2)-(0.04)^(2))" "…(1)`
At `y=3" cm"=0.03" m",v=4" m"//"s"`
`:." "4=omega sqrt(a^(2)-(0.03)^(2))" "...(2)`
Dividing (2) by (1), we get a = 0.05 = 5 cm