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A particle of mass 10 gm is describing S...

A particle of mass 10 gm is describing S.H.M. along a straight line with period of 2 sec and amplitude of 10 cm . Its kinetic energy when it is at 5 cm from its equilibrium position is

A

`37.5pi^(2)" erg"`

B

`3.75pi^(2)" erg"`

C

`375pi^(2)" erg"`

D

`0.375pi^(2)" erg"`

Text Solution

Verified by Experts

The correct Answer is:
C

Kinetic energy `K=(1)/(2)m omega^(2)(a^(2)-y^(2))`
`=(1)/(2)xx10xx((2pi)/(2))^(2)[10^(2)-5^(2)]=375" "pi^(2)` erg
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DISHA PUBLICATION-OSCILLATIONS -Exercise-1 : Concept Builder (TOPIC 1: Displacement, Phase, Velocity, Acceleration and Energy in S.H.M.)
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  18. If y = 2 (cm) sin[(pi t)/(2)+phi] then the maximum acceleration of the...

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