A body of mass 5 gm is executing S.H.M. about a point with amplitude 10 cm . Its maximum velocity is 100 cm / sec . Its velocity will be 50 cm / sec at a distance

Options

A. 5
B. `5sqrt(2)`
C. `5sqrt(3)`
D. `10sqrt(2)`

Answer

C

Explanation

`v_("max")=100=a omega,omega=100//a=100//10=10" rad"//"s"`
`v^(2)=omega^(2)(a^(2)-y^(2))" or "50^(2)=10^(2)(10^(2)-y^(2))" or "25=100-y^(2)`
or `y=sqrt(75)=5sqrt(3)` cm.