Home
Class 12
PHYSICS
A forced oscillator is acted upon by a f...

A forced oscillator is acted upon by a force, `F=F_(0)sinomegat`. The amplitude of the oscillator is given by `A=(55)/(sqrt((2omega^(2)-36omega+9)))`
What is the resonance angular freuqnecy (in rad/s)?

A

2 unit

B

9 unit

C

18 unit

D

36 unit

Text Solution

Verified by Experts

The correct Answer is:
B
At resonance, amplitude of oscillation is maximum
`implies2 omega^(2)-36omega+9` is minimum
`implies4omega-36=0` (derivative is zero) `impliesomega=9`
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    DISHA PUBLICATION|Exercise Exercise-2 : Concept Applicator|28 Videos

  • OSCILLATIONS

    DISHA PUBLICATION|Exercise Exercise-1 : Concept Builder (TOPIC 2: Time Period, Frequency, Simple Pendulum and Spring Pendulum)|31 Videos

  • NUCLEI

    DISHA PUBLICATION|Exercise EXERCISE - 2 (CONCEPT APPLICATOR)|30 Videos

  • PHYSICAL WORLD, UNITS AND MEASUREMENTS

    DISHA PUBLICATION|Exercise Exercise - 2 : Concept Applicator|30 Videos

Similar Questions

Explore conceptually related problems

A particle, with restoring force proportional to displacement and resulting force proportional to velocity is subjected to a force F sin omega t . If the amplitude of the particle is maximum for omega = omega_(1) , and the energy of the particle is maximum for omega=omega_(2) , then

If a body oscillates at the angular frequency (omega_(d)) of the driving force, then the oscillations are called

The SHM of a particle is given by the equation x=2 sin omega t + 4 cos omega t . Its amplitude of oscillation is

A simple harmonic motion is represented by x(t) = sin^(2)omega t - 2 cos^(2) omega t . The angular frequency of oscillation is given by

The angular velocity of a particle is given by the equation omega =2t^(2)+5rads^(-1) . The instantaneous angular acceleration at t=4 s is

Demonstrate thatat low damping the quality factor Q of a circuit maintaining forced oscillations is approximately equal to omega_(0)//Delta omega , where omega_(0) is the natural oscillation frequency , Delta omega is the width of the resonance curve I(omega) at the " height " which is sqrt(2) times less than the resonance current amplitude.

A point particle is acted upon by a restoring force –kx3 . The time period of oscillation is T when the amplitude is A. The time period for an amplitude 2A will be :

A simple harmonic oscillator of angular frequency 2 "rad" s^(-1) is acted upon by an external force F = sint N . If the oscillator is at rest in its equilibrium position at t = 0 , its position at later times is proportional to :-