A mass (M) is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T. If the mass is increased by m, the time period becomes `(5T)/3`. Then the ratio of `m/M` is .

Options

A. `(25)/(9)`
B. `(16)/(9)`
C. `(5)/(3)`
D. `(3)/(5)`

Answer

B

Explanation

`T=2pi sqrt((M)/(k))=2pi sqrt((M+m)/(k))`
`implies(25)/(9)(M)/(k)=(M+m)/(k)implies(m)/(M)=(16)/(9)`