Two simple harmonic are represented by the equation `y_(1)=0.1 sin (100pi+(pi)/3) and y_(2)=0.1 cos pit`.
The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is.

Options

A. `(pi)/(3)`
B. `(-pi)/(6)`
C. `(pi)/(6)`
D. `(-pi)/(3)`

Answer

B

Explanation

`v_(1)=(dy_(1))/(dt)=0.1xx100pi cos (100pi t+(pi)/(2))`
`:.` Phase diff. `=phi_(1)-phi_(2)=(pi)/(3)-(pi)/(2)=(2pi-3pi)/(6)=-(pi)/(6)`