A cylindrical of wood (density `= 600 kg m^(-3)`) of base area `30 cm^(2)` and height `54 cm`, floats in a liquid of density `900 kg^(-3)` The block is deapressed slightly and then released. The time period of the resulting oscillations of the block would be equal to that of a simple pendulum of length (nearly) :

Options

A. 52 cm
B. 65 cm
C. 39 cm
D. 26 cm

Answer

C

Explanation

h = Length of block immerged in water
`mg=F_(B)impliesrho Al_(g)=rho_(B)Ahg`
`650xxAxx54xx10^(-2)g=900xxAxxhg`
`impliesh=0.39m=39" cm."`