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A parallel plate capacitor of capacitanc...

A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20V. If a dielectric material of dielectric constant `k=(5)/(3)` is inserted between the plates, the magnitude of the induced charge will be

A

`1.2nC`

B

`0.3nC`

C

`2.4nC`

D

`0.9nC`

Text Solution

Verified by Experts

The correct Answer is:
A
Charge on capacitor `Q(i)=CV`
After inserting dielectic of dielectric constat =K
`Q_(f)=(kC)V`
Induced charges on dielectric
`Q_("ind")=Q_(f)-Q_(i)=KCV-CV`
`=(K-1)CV=(5/3-1)xx90pF=2V=1.2nC`
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DISHA PUBLICATION-ELECTROSTATIC POTENTIAL AND CAPACITANCE-EXERCISE 2: CONCEPT APPLICATOR
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