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An air capacitor of capacity C = 10 mu F...

An air capacitor of capacity `C = 10 mu F` is connected to a constant voltage battery of `12 V`. Now the space between the plates is filled with a liquid of dielectirc constant `5`. The charge that flows now from battery to the capacitor is

A

`120muC`

B

`600muC`

C

`480muC`

D

`24muC`

Text Solution

Verified by Experts

The correct Answer is:
C
`q_(1)=C_(1)V=10xx12=120muC`
`q_(2)=C_(2)V=KC_(1)xxV=5xx10xx12=600muC`
Additional charge that flows
`=q_(2)-q_(1)=600-120=480muC`
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DISHA PUBLICATION-ELECTROSTATIC POTENTIAL AND CAPACITANCE-EXERCISE -1: CONCEPT BUILDER
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