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Two capacitors of capacitances C(1) and ...

Two capacitors of capacitances `C_(1)` and `C_(2)` are connected in parallel across a battery. If` Q_(1)` and `Q_(2)` respectively be the charges on the capacitors, then `(Q_(1))/(Q_(2))` will be equal to

A

`(C_(2))/(C_(1))`

B

`(C_(1))/(C_(2))`

C

`(C_(1)^(2))/(C_(2)^(2))`

D

`(C_(2)^(2))/(C_(1)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B

In parallel, potential is same say V
`(Q_(1))/(Q_(2))=(C_(1)V)/(C_(2)V)=(C_(1))/(C_(2))`
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DISHA PUBLICATION-ELECTROSTATIC POTENTIAL AND CAPACITANCE-EXERCISE -1: CONCEPT BUILDER
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