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In a neon discharge tube 2.9 xx 10^(18) ...

In a neon discharge tube `2.9 xx 10^(18) Ne^(+)` ions move to the right each second while `1.2 xx 10^(18)` eletrons move to the left per second. Electron charge is `1.6 xx 10^(-9) C`. The current in the discharge tube

A

0.27 A to the right

B

0.66 A to the right

C

0.66 A to the left

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
Current, `I = (2.9 xx 10^(18) + 1.2 xx 10^(18) ) xx 1.6 xx 10^(-19) ` towards right.
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