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You are given two resistances R(1) and R...

You are given two resistances `R_(1)` and `R_(2)`. By using them in series and in parallel, you can obtain four resistances of ` 8Omega` and `1.5Omega`. The value of `R_(1)` and `R_(2)` are

A

`1 Omega, 7 Omega`

B

`1.5 Omega, 6.5 Omega`

C

`3 Omega, 5 Omega`

D

`2 Omega, 6 Omega`

Text Solution

Verified by Experts

The correct Answer is:
D
`R_1 = 2 Omega and R_2 = Omega`
In series, `R= R_1 + R_2 = 8 Omega`
In parallel, `(1)/(R)= (1)/( R_1) + (1)/(R_2) = (1)/(2) + (1)/(6) = (4)/(6)`
`therefore R= (6)/(4)=1.5 Omega`
`therefore` We can get `1.5 Omega, 2 Omega, 6 Omega and 8Omega` resistors by ` 2 Omega and 6 Omega` resistors.
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