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Three resistance each of 4Omega are conn...

Three resistance each of `4Omega` are connected to form a triangle. The resistance between any two terminals is

A

`12 Omega`

B

`2 Omega`

C

`6 Omega`

D

`8//3 Omega`

Text Solution

Verified by Experts

The correct Answer is:
D
The two resistance are connected in series and the resultant is connected in parallel with the third resistance.
`therefore R.= 4 Omega + 4 Omega = 8 Omega and (1)/ ( R^(**))= (1)/(8) + (1)/(4) = (3)/(8)`
or `R.. = (8)/(3) Omega`
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