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The potential difference betwee11 the te...

The potential difference betwee11 the terminals of a cell in an open circuit is 2.2 V. When a resistor of `5 Omega` is connected across the terminals of the cell, the potential difference between the terminals of the cell is found to be 1.8 V. The internal resistance of the cell is

A

`(7)/(12) Omega`

B

`(10)/(9) Omega`

C

`(9)/(10) Omega`

D

`(12)/(7) Omega`

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The correct Answer is:
To find the internal resistance of the cell, we can follow these steps: ### Step 1: Identify the given values - Open circuit potential difference (emf, \( E \)) = 2.2 V - Potential difference across the terminals when a resistor is connected (\( V \)) = 1.8 V - Resistance of the connected resistor (\( R \)) = 5 Ω ### Step 2: Use Ohm's Law to find the current When the resistor is connected, the potential difference across it is 1.8 V. We can use Ohm's law to find the current (\( I \)) flowing through the circuit: \[ I = \frac{V}{R} = \frac{1.8 \, \text{V}}{5 \, \Omega} = 0.36 \, \text{A} \] ### Step 3: Apply Kirchhoff’s Voltage Law (KVL) According to KVL, the sum of the potential differences in a closed loop is equal to zero. For our circuit: \[ E - I \cdot R - V = 0 \] Where: - \( E \) is the emf of the cell (2.2 V), - \( I \cdot R \) is the voltage drop across the internal resistance (\( r \)) of the cell, - \( V \) is the voltage across the external resistor (1.8 V). Rearranging gives: \[ E = I \cdot r + V \] ### Step 4: Substitute the known values Substituting the known values into the equation: \[ 2.2 \, \text{V} = I \cdot r + 1.8 \, \text{V} \] \[ 2.2 \, \text{V} - 1.8 \, \text{V} = I \cdot r \] \[ 0.4 \, \text{V} = I \cdot r \] ### Step 5: Substitute the current value into the equation Now substitute \( I = 0.36 \, \text{A} \): \[ 0.4 \, \text{V} = 0.36 \, \text{A} \cdot r \] ### Step 6: Solve for internal resistance (\( r \)) Rearranging the equation gives: \[ r = \frac{0.4 \, \text{V}}{0.36 \, \text{A}} \approx 1.11 \, \Omega \] ### Final Answer The internal resistance of the cell is approximately \( 1.11 \, \Omega \). ---

To find the internal resistance of the cell, we can follow these steps: ### Step 1: Identify the given values - Open circuit potential difference (emf, \( E \)) = 2.2 V - Potential difference across the terminals when a resistor is connected (\( V \)) = 1.8 V - Resistance of the connected resistor (\( R \)) = 5 Ω ### Step 2: Use Ohm's Law to find the current ...
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