The resistance of an ammeter is 13 Omega...

The resistance of an ammeter is `13 Omega` and its scale is graduated for a current upto `100 A`. After an additional shunt has been connected to this ammeter it becomes possible to measure currents upto `750 A` by this meter. The value of shunt resistance is

`2 Omega`

`0.2 Omega`

`2 k Omega`

`20 Omega`

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The correct Answer is:

We know
`(I)/( I_(S))= 1+ (G)/( S) rArr (750)/( 100) = 1 + (13)/(S) rArr S =2 Omega`

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