The figure shows three circuits I, II and III which are connected to a 3V battery. If the powers dissipated by the configurations I, II and III are `P_1 , P_2 and P_3` respectively, then:

Options

A. `P_1 gt P_2 gt P_3`
B. `P_1 gt P_3 gt P_2`
C. `P_2 gt P_1 gt P_3`
D. `P_3 gt P_2 gt P_1`

Answer

C

Explanation

From the given circuit, net resistances
`R_I = 1 Omega, R_II = 1//2 Omega, R_III = 3//2 Omega`
it is clear that `R_3 gt R_1 gt R_2`
Hence, `P_(3) lt P_(1) lt P_(2)` As Power (P) `= (V^2)/( R) rArr P prop (1)/ (R )`