A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is `0.2xx10^(-4)T`, then the emf developed between the two ends of hte conductor is

Options

A. 5mV
B. `50 mu V`
C. `5mu V`
D. 50 mV

Answer

B

Explanation

`l=1m, omega=5 rad//s, B=0.2xx10^(-4)T`
`epsilon=(B omega l)/(2)=(0.2xx10^(-4)xx5xx1)/(2)=50mu V`