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The coefficient of self-inductance of a ...

The coefficient of self-inductance of a solenoid is `0.18 mH`. If a crude of soft iron of relative permeability `900` is inserted, then the coeffcient of self-inductance will become nearly

A

5.4 mH

B

162 mH

C

0.006 mH

D

0.0002 mH

Text Solution

Verified by Experts

The correct Answer is:
B
`L=mu_(0)nI`
`therefore (L_(2))/(L_(1))=(mu)/(mu_(0)) " " …..(because "n and I are same")`
`therefore L_(2)=mu_(1)Li=900xx0.18=162` mH
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